Likelihood of regression to normal glucose regulation also increased for individuals with prediabetes taking vitamin D<\/p>\n<\/h3>\n
By Elana Gotkine HealthDay Reporter<\/b><\/p>\n
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TUESDAY, Feb. 7, 2023 (HealthDay News) — For individuals with prediabetes, vitamin D supplementation is associated with a reduced risk for progression to diabetes, according to a review published online Feb. 7 in the Annals of Internal Medicine<\/em>.<\/p>\n Anastassios G. Pittas, M.D., from Tufts Medical Center in Boston, and colleagues examined whether administration of vitamin D reduces the risk for diabetes among individuals with prediabetes in a systematic review and meta-analysis. Data were included from three randomized trials, which assessed cholecalciferol 20,000 IU weekly, cholecalciferol 4,000 IU daily, or eldecalcitol 0.75 mcg daily compared to matching placebos.<\/p>\n The researchers found that in adjusted analyses, the risk for diabetes was significantly reduced with vitamin D (hazard ratio, 0.85), with a 3.3 percent three-year absolute risk reduction. In prespecified subgroups, there was no difference in the effect of vitamin D. Cholecalciferol reduced the risk for diabetes significantly among participants assigned to the vitamin D group who maintained an intratrial mean serum 25-hydroxyvitamin D level of at least 125 nmol\/L versus 50 to 74 nmol\/L during follow-up (hazard ratio, 0.24), with an 18.1 percent three-year absolute risk reduction. The likelihood of regression to normal glucose regulation was increased with vitamin D (rate ratio, 1.30). There were no differences in the rate ratios for adverse events, including kidney stones, hypercalcemia, hypercalciuria, and death.<\/p>\n “Vitamin D in people with prediabetes was beneficial in decreasing risk for diabetes and increasing the likelihood of regression to normal glucose regulation, with no offsetting safety signals,” the authors write.<\/p>\n Abstract\/Full Text (subscription or payment may be required)<\/a><\/p>\n Editorial (subscription or payment may be required)<\/a><\/p>\n <\/i><\/p>\n